the larger of the two numbers is five more than twice the smaller number. the sum of the two numbers is 38β
Accepted Solution
A:
Answer:Step-by-step explanation:l = 2s+5, l + s = 38. Then by direct substitution, 2s+5 + s = 38, or
3s+5 = 38, or 3s = 33, or s = 11, the smaller number. The larger number is 38-11 = 27.